REDOX answers |
1 |
Assign Oxidation numbers then use them to find out what has been oxidised and what has been reduced: Blue = Oxidised Red = Reduced |
2 |
For each of 1a - e, identify the oxidising agent and reducing agent: |
3 Define the following terms: |
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a | CuO | + | H2 | à | Cu | + | H2O | Ox Agent | Red Agent | a | Oxidation | Loss of electrons | |||
Cu = +2 | H = 0 | Cu = 0 | H = +1 | a | CuO | H2 | |||||||||
b | 2I- | + | Br2 | à | I2 | + | 2Br- | b | Reduction | Gain of electrons | |||||
I = -1 | Br = 0 | I = 0 | Br = -1 | b | Br2 | I- | |||||||||
c | Mg | + | 2Ag+ | à | Mg2+ | + | 2Ag | c | Oxidising agent | Oxidises another species while itself is reduced | |||||
Mg = 0 | Ag = +1 | Mg = 2+ | Ag = 0 | c | Ag+ | Mg | |||||||||
d | 2Fe2+ | + | Cl2 | à | 2Fe3+ | + | 2Cl- | d | Reducing agent | Reduces another species while itself is Oxidised | |||||
Fe = +2 | Cl = 0 | Fe = +3 | Cl = -1 | d | Cl2 | Fe2+ | |||||||||
e | Br2 | + | H2S | à | 2HBr | + | S | ||||||||
Br = 0 | S = -2 | Br = -1 | S = 0 | e | Br2 | H2S |