|
|
|
|
HCl |
|
|
|
|
CH3COOH |
C2H5OH |
à |
CH3COOC2H5 |
H2O |
|
Moles start |
0.525 |
0.515 |
|
0.314 |
0.556 |
|
Moles eqm |
0.318 |
|
|
|
|
|
Moles reacted |
|
|
|
|
|
|
Conc eqm |
|
|
|
|
|
Calculation:
1.
Calculate the number of
moles of CH3COOH reacted using the table
2.
Use the molar ratio to calculate how
many moles of C2H5OH reacted
3.
Use the molar ratio to calculate how
many moles of CH3COOC2H5
produced. This is the moles at equilibrium.
4.
Use the molar ratio to calculate how
many moles of H2O produced. This is the moles at
equilibrium.
5.
Now go back and calculate the moles of
C2H5OH at equilibrium.
6.
Remember all these amounts need to be as
concentrations. Your total volume was 100cm3.
Use the concentration moles formula to calculate the
concentration at equilibrium (Conc = moles x 1000/vol). |